READ Free Dumps For Oracle- 1z0-803
| Question ID 21939 | Given the code fragment:
System.out.println ("Result:" +3+5);
System.out.println ("result:" + (3+5));
What is the result?
|
| Option A | Result: 8
Result: 8
|
| Option B | Result: 35
Result: 8
|
| Option C | Result: 8
Result: 35
|
| Option D | Result: 35
Result: 35
|
| Correct Answer | B |
Explanation Explanation: In the first statement 3 and 5 are treated as strings and are simply concatenated. In the first statement 3 and 5 are treated as integers and their sum is calculated.
| Question ID 21940 | Given:
public class Main {
public static void main(String[] args) throws Exception { doSomething();
}
private static void doSomething() throws Exception {
System.out.println("Before if clause");
if (Math.random() > 0.5) {
throw new Exception();
}
System.out.println ("After if clause");
}
}
Which two are possible outputs?
|
| Option A | Before if clause
Exception in thread "main" java.lang.Exception
At Main.doSomething (Main.java:8)
At Main.main (Main.java:3)
|
| Option B | Before if clause
Exception in thread "main" java.lang.Exception
At Main.doSomething (Main.java:8)
At Main.main (Main.java:3)
After if clause
|
| Option C | Exception in thread "main" java.lang.Exception
At Main.doSomething (Main.java:8)
At Main.main (Main.java:3)
|
| Option D | Before if clause
After if clause
|
| Correct Answer | A,D |
Explanation Explanation: The first println statement, System.out.println("Before if clause");, will always run. If Math.Random() > 0.5 then there is an exception. The exception message is displayed and the program terminates. If Math.Random() > 0.5 is false, then the second println statement runs as well. Incorrect answers: B: The second println statement would not run. C: The first println statement will always run.